# A more realistic car would cause the wheels to spin in a manner that would result in the ground pushing it forward with a constant force (in contrast to the constant power in Part A). If such a sports car went from zero to 29.0 mph in time 1.50 s , how long would it take to go from zero to 58.0 mph

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Answer:It would take 3.00 sStep-by-step explanation:For a constant force system, the acceleration (a) of the system is constant.In the first instance,Initial velocity = 0 mphfinal velocity = 29.0 mphtime taken = 1.50 s[tex]acceleration = \frac{final velociity(v) - initial velocity (u)}{time taken}[/tex][tex]acceleration = \frac{29.0 - 0}{1.50}[/tex][tex]acceleration = 19.33 mph^{2}[/tex]Since the system is a constant force system,Initial velocity = 0 mphfinal velocity = 58.0 mphtime taken = ?[tex]acceleration = \frac{final velociity(v) - initial velocity (u)}{time taken}[/tex][tex]19.33 = \frac{58.0 - 0}{t}[/tex]t = \frac{58.0}{19.33} = 3.00 s
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