A triangle has sides of lengths 10 cm and 16 cm and the measure of the angle between them is 130 degrees. Find the area of the triangle.

Answer:The area of the triangle is 61.2 sq. cm.Step-by-step explanation:Given : A triangle has sides of lengths 10 cm and 16 cm and the measure of the angle between them is 130 degrees.To find : The area of the triangle?Solution : The area of triangle when two sides and one angle between them is given is [tex]A=\frac{1}{2}\times a\times b\times \sin\theta[/tex]Where, a and b are the sides of the triangle a=10 cm and b=16 cm[tex]\theta=130^\circ[/tex] is the angle between two sides Substituting the values in the formula,[tex]A=\frac{1}{2}\times 10\times 16\times \sin 130[/tex][tex]A=80\times 0.766[/tex][tex]A=61.28cm^2[/tex]Therefore, The area of the triangle is 61.2 sq. cm.