Can someone please help me? :)Estimate the size of a crowd standing along a 1/4 mile section of a parade route that is 5 feet deep on both sides of the street. Assume that 10 people occupy a square measuring 5 feet by 5 feet.A. 2640 peopleB. 3960 peopleC. 5280 peopleD. 7920 people

The size of a crowd standing along with a 1/4 mile section of a parade route: 5280 peopleFurther explanation Comparison is an effort to compare two or more objects in terms of shape or size, or numberProportional Comparisons are comparisons of two or more numbers where one number increases, the other numbers also increaseCan be formulated[tex]\frac{x1}{y1}=\frac{x2}{y2}[/tex]so that if:x = 2then[tex]y=\frac{y}{x}\times\:2[/tex]While the reversal value comparison is the comparison of two or more numbers where one number increases, the other number decreases in valueCan be formulated[tex]\frac{x1}{y2}=\frac{x2}{y1}[/tex]so that if:x = 2then[tex]y=\frac{x}{y}\times\:2[/tex]The size of a crowd who can see the parade can be calculated using the principle of proportional comparison1. We calculate the ratio of people and areas that can be occupied The question stated that 10 people occupy a square measuring 5 feet by 5 feetmeans the area occupied by 10 people = 5 ft x 5 ft = 25 ft²so the ratio is :[tex]\frac{10}{25}[/tex]2. We calculate the area of ​​the road that can be occupied when viewing the parade Because there are 1/4 mile section of a parade route and 5 feet deep on both sides of the street, the total area1 mile = 5280 ft1/4 mile = 1320 ftTotal area = 1320 ft x 5 ft (deep) x 2 (both sides of the street) = 13200 ft²Then the comparison of points 1 and 2 can be used to calculate the total number of people who saw the parade[tex]\frac{10\:people}{25\:ft^2\:area}=\frac{total\:people\:watched}{13200\:ft^2\:total\:area}[/tex]Total people = [tex]\frac{10\:\times\:13200}{25}[/tex]Total people = 5280 (C)Learn more Divide 80 in a ratio of 3: 2 of 19.5 is 70.59 average weight of the top 5 fish: parade, street, area, crowd, comparison