# Tempestt graphs a function that has a maximum located at (β4, 2). Which could be her graph? On a coordinate plane, a parabola opens up. It goes through (negative 6, 6), has a vertex at (negative 4, 2), and goes through (negative 2, 6). On a coordinate plane, a parabola opens up. It goes through (2, 6), has a vertex at (4, 2), and goes through (6, 6). On a coordinate plane, a parabola opens down. It goes through (negative 6, negative 2), has a vertex at (negative 4, 2), and goes through (negative 2, negative 2). On a coordinate plane, a parabola opens down. It goes through (2, negative 2), has a vertex at (4, 2), and goes through (6, negative 2).

Question

Answer:

Answer:Option C matches the conditions.Step-by-step explanation:Tempestt graphs a function that has a maximum located at (-4,2).
Now, we have to select from the given options that will satisfy the given conditions.
Since the graph of the function has a maximum at (-4,2). therefore, we can conclude that if the function is of a parabola then it must open down and the vertex of the parabola will be the maximum point i.e. (-4,2).
So, option C matches the conditions which give 'On a coordinate plane, a parabola opens down. It goes through (-6,-2), has a vertex at (-4, 2), and goes through (-2,-2)'. (Answer)
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