# The zeros for f(x)=x^4-4x^3-9x^2+36x are

Question

Answer:

x^4 - 4x^3 - 9x^2 + 36x = 0x(x^3 - 4x^2 - 9x + 36) = 0

x(x^2(x - 4) - 9(x - 4) = 0

x(x + 3)(x - 3)(x - 4) = 0

the zeroes are -3, 0, 3, 4 Answer

solved

general
8 months ago
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