Which is a solution to the equation?x − 3x − 5 = 35x = −8x = −5x = 2x = 10

Answer:-The solutions are:\(x = 10\)\(x = -2\)-Solve the equation:\((x-3)(x-5) =35\)-Use Distributive property to multiply the \(x -3\) by \(x -5\) and combine like terms:\((x-3)(x-5) =35\)\(x^2-8x + 15 = 35\)-Subtract 35 from 15:\(x^2 - 8x + 15 -35 = 35 -35\)\(x^2 - 8x - 20 =0\)-Use the quadratic formula and substitute 1 for \(a\), -8 for \(b\) , and -20 for \(c\) :\(\frac{}-b\pm\sqrt{}b^2-4ac{} {}{}2a{}\)\(\frac{}-(-8)\pm\sqrt{}(-8)^2-4(-20){} {}{}2{}\)-Simplify the 8 by the exponent 2:\(x = \frac{}-(-8)\pm\sqrt{}(-8)^2-4(-20){} {}{}2{}\)\(x = \frac{}-(-8)\pm\sqrt{}64-4(-20){} {}{}2{}\)-Multiply -20 by -4:\(x = \frac{}-(-8)\pm\sqrt{}64-4(-20){} {}{}2{}\)\(x = \frac{}-(-8)\pm\sqrt{}64+80{} {}{}2{}\)-Add both 64 and 80 together:\(x = \frac{}-(-8)\pm\sqrt{}64+80{} {}{}2{}\)\(x = \frac{}-(-8)\pm\sqrt{}144{} {}{}2{}\)-Take the square root of 144:\(x = \frac{}-(-8)\pm\sqrt{}144{} {}{}2{}\)\(x = \frac{}-(-8)\pm 12 {}{}2{}\)-Change -8 to 8 , because negative and negative equals a positive:\(x = \frac{}-(-8)\pm 12 {}{}2{}\)\(x =\frac{}8\pm 12 {}{}2{}\)-Solve the equation when \(\pm\) is in addition. So, you would add 8 and 12 together:\(x =\frac{}8\pm 12 {}{}2{}\)\(x =\frac{}8 + 12 {}{}2{}\)\(x =\frac{}20 {}{}2{}\)-Divide 20 by 2:\(x =\frac{}20{}{}2{}\)\(x = 10\)So, the first answer is \(x = 10\).-To find the second answer, you need to solve the equation when \(\pm\) is in subtraction. So, you would subtract both 8 and 12 together:\(x =\frac{}8\pm 12 {}{}2{}\)\(x =\frac{}8 - 12 {}{}2{}\)\(x = \frac{}-4{}{}2{}\)-Divide -4 by 2:\(x = \frac{}-4{}{}2{}\)\(x = -2\)So, the second answer is \(x = -2\) .The solutions are:\(x = 10\)\(x = -2\)