1. Find the perimeter and area of a rectangle with a length of 3.2 m and a width of 1.5 m.A) p=4.7 m; A=2.25 m^2B) p=4.7 m; A=4.8^2C) p=9.4 m; A=2.4 m^2D) p=9.4 m; A= 4.8^22. Find the area of a triangle with a base of 27 feet and a height of 14 feet.A) 41 ft^2B) 82 ft^2C) 189 ft^2D) 378 ft^2

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Answer:
1. D) p=9.4 m; A= 4.8 m^2 2. C) 189 ft^2 1. Find the perimeter and area of a rectangle with a length of 3.2 m and a width of 1.5 m. The perimeter of a rectangle is simply twice the sum of it's length and width, so 2(3.2m + 1.5 m) = 2*4.7 = 9.4 m The area of a rectangle is the product of its length and width, so 3.2 m * 1.5 m = 4.8 m^2 Of the available choices, D matches with p=9.4 m; A= 4.8 m^2 2. Find the area of a triangle with a base of 27 feet and a height of 14 feet. The area of a triangle is 1/2 base times height, so 0.5 * 27 ft * 14 ft = 189 ft^2 Of the available choices, C matches with 189 ft^2
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general 10 months ago 4183