15x+31y=−3 x=−y+3 ​

15x + 31y = -3
x = -y + 3 ​

To solve this system, substitute -y + 3 into 15x + 31y = -3 for x, and solve algebraically for y.

15x + 31y = -3
15(-y + 3) + 31y = -3
-15y + 45 + 31y = -3
16y + 45 = -3
16y = -48
y = -3

Substitute -3 for y into either of the original equations and solve algebraically for x.

x = -y + 3
x = -(-3) + 3
x = 3 + 3
x = 6

Finally, substitute both x- and y-values into both original equations to check work.

15x + 31y = -3
15(6) + 31(-3) = -3
90 + (-93) = -3
-3 = -3

6 = -(-3) + 3)
6 = 3 + 3
6 = 6

Answer:
x = 6
y = -3

(6, -3)