2 cubes each of volume 64 cm^3 are joined end to end. Find the surface area of the resulting cuboid.

Volume of each cube=[tex]64 \: cm {}^{3} [/tex]
So,edge of each cube =[tex] \sqrt[3]{64} = 4[/tex]
If we join two cubes, then length of cuboid so formed = (4 + 4) = 8.0 cm
Breadth of cube = 4.0 cm
and Height of cube = 4.0 cm

Therefore, surface area of resulting cuboid
= 2 × [lb + bh + hl]
= 2 × [8 × 4 + 4 × 4 + 4 × 8]
= 160 cm²