3w2-12w+12=0

Question

Answer:

$w_{1,2}=\frac{-(-12)\pm \sqrt{0}}{2\cdot 3}$

$w_{1,2}=\frac{-(-12)\pm \sqrt{(-12)^{2}-4\cdot 3\cdot 12}}{2\cdot 3}$ $w=\frac{-(-12)}{2\cdot 3}$

$w=2$

solved

general 11 months ago 662