A circle has a radius of 7/4 units and is centered at (βˆ’2.5,βˆ’4.4)

Question
Answer:
Answer:[tex](x+2.5)^2+(y+4.4)^2=\dfrac{49}{16}[/tex].Step-by-step explanation:Consider the complete question is " A circle has a radius of 7/4 units and is centered at (βˆ’2.5,βˆ’4.4). Write the equation of this circle." The standard form of a circle is [tex](x-h)^2+(y-k)^2=r^2[/tex] where, (h,k) is center and r is radius of the circle. Substitute h=-2.5, k=-4.4 and r=7/4 in the above formula. [tex](x-(-2.5))^2+(y-(-4.4))^2=(\dfrac{7}{4})^2[/tex] [tex](x+2.5)^2+(y+4.4)^2=\dfrac{49}{16}[/tex] Hence the equation of circle is [tex](x+2.5)^2+(y+4.4)^2=\dfrac{49}{16}[/tex].
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general 11 months ago 8901