A theater charges $50 per ticket for seats in section a, $40 per ticket for seats in section b, and $20 per ticket for seats in sectionc. for one play, 9,500 tickets were sold for a total of $335,000 in revenue. if 500 more tickets in section b were sold than the other two sections combined, how many tickets in each section were sold?
Question
Answer:
The first thing we must do for this case is to define variables.We have then:
x: ticket for seats in section a
y: ticket for seats in section b
z: ticket for seats in section c
We write the system of equations:
50x + 40y + 20z = 335000
x + y + z = 9500
y = x + z + 500
Solving the system we have:
x = 1500
y = 5000
z = 3000
Answer:
ticket for seats in section a = 1500
ticket for seats in section b = 5000
ticket for seats in section c = 3000
solved
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