Alan has two more than twice as many chocolates as does alice, and half as many chocolates as does nadia. if alice has βa' number of chocolates, then in terms of βa', how many chocolates do alan, alice and nadia have
Question
Answer:
Alan has two more than twice as many chocolates as does aliceAlan = 2Alice + 2 ----(1)
Alan has half as many chocolates as does nadia
Alan = 1/2 Nadia
so Nadia = 2Alan ----(2)
if Alice has 'a' number of chocolates
from (1)
Alan = 2a + 2 ----(3)
from (2) and (3)
Nadia = 2 (2a+2) = 4a+4 ----(4)
So Alan Alice and Nadia have
(2a+2) + a + (4a+4) = 7a+ 6 #
solved
general
10 months ago
2017