Arrange the circles (represented by their equations in general form) in ascending order of their radius lengths.Tilesx2 + y2 − 2x + 2y − 1 = 0x2 + y2 − 4x + 4y − 10 = 0 x2 + y2 − 8x − 6y − 20 = 04x2 + 4y2 + 16x + 24y − 40 = 0 5x2 + 5y2 − 20x + 30y + 40 = 02x2 + 2y2 − 28x − 32y − 8 = 0x2 + y2 + 12x − 2y − 9 = 0

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There is 2 ways we can know what is the radius of each circles. The first is graphing the equation which I consider tedious. The second is algebraically altering the equation into the form: . Given that, the answer is:x2 + y2 − 2x + 2y − 1 = 0 (r = 1.73)x2 + y2 − 4x + 4y − 10 = 0  (r = 4.24)4x2 + 4y2 + 16x + 24y − 40 = 0 (r = 4.80)x2 + y2 − 8x − 6y − 20 = 0 (r = 6.7)x2 + y2 + 12x − 2y − 9 = 0 (r = 6.78)2x2 + 2y2 − 28x − 32y − 8 = 0 (r = 11)
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general 6 months ago 6047