C an anyone solve this 3(2b + 3)2 = 36and if so what is it

[tex]3(2b + 3)^2 = 36[/tex]

Divide by 3 on both sides:
[tex](2b + 3)^2 = 12[/tex]

Square root both sides:
[tex]2b + 3= \pm \sqrt{12} [/tex]

Take away 3 from both sides:
[tex]2b= \pm \sqrt{12} - 3 [/tex]

Divide by 2 on both sides:
[tex]b= \dfrac{ \sqrt{12} -3 }{2} \ or \ b= \dfrac{ -\sqrt{12} -3 }{2} [/tex]

Answer:
[tex]b= 0.23 \ or \ -3.23[/tex]