G(n) = n 2 + 4 + 2n h(n) = −3n + 2 find (g ⋅ h)(1)

This is multiplication.

First find g(n)*h(n).  It is (n^2 + 4 + 2n)*(-3n+2).  You could now do the algebra, but you could also substitute 1 for n right now.

(g*h)(1) = (1 + 4 + 2)(-3 + 2) = (7)(-1) = -7 (answer)

Please, use " ^ " to indicate exponentiation.  n 2 doesn't cut it.