HELP. TODD.Kristine has a bedroom wall that is shaped like a trapezoid with a height of 9 ft, a top base of 12 ft, and a bottom base of 15 ft. In the middle of this wall is a circular window whose radius is 3 ft.What is the area of the wall without the window?Use 3.14 for pi.Enter your answer in the box.

First, we figure out the area of the wall, which is shaped like a trapezoid. The equation for the area of a trapezoid is 
[tex] \frac{1}{2} (a+b)h[/tex]
where a is the top base, b is the bottom base and h is the height.
Substitute your given values into the equation and solve:
A=1/2(12+15)9
A=4.5(27)
Area of the wall= 121.5ft²

Now we figure out the area of the of the circular window. The formula for the area of a circle is 
[tex] \pi r^{2} [/tex]
where r is the radius
Substitute your given values into the equation and solve:
pi×3²
[tex]9 \pi =28.27433388 ft^{2} [/tex]

Now finally minus the area of the window from the area of the wall.
121.5-28.27433388=93.22566612
To 1 d.p., the area of the wall without the window is 93.2ft²