HelpDetermine which equation is parallel to line jk and which is perpendicular to line jk.

Answer:5x + 3y = 13 parallel.6x - 10y = 7 perpendicular.Step-by-step explanation:Two lines with slopes [tex]m_1[/tex] and [tex]m_2[/tex] are parallel when [tex]m_1=m_2[/tex] and are perpendicular when [tex]m_1*m_2=-1[/tex] Now determine the slope of all the lines The line jk passes through the points (-5,5) and (1,-5) so its slope is [tex]\frac{-5-5}{1-(-5)}=\frac{-10}{6}=-\frac{5}{3}[/tex] To determine the slope of the lines in the blue rectangles, isolate y from each one and the coefficient of x is the slope 5x-3y = 8 ------> y = (5/3)x + 8/3 ------> slope 5/3 Neither parallel nor perpendicular. 6x+10y = 11 ------> y = (-6/10)x + 11/10 = (-3/5)x + 11/10 ------> slope -3/5 Neither parallel nor perpendicular. 5x + 3y = 13 ------> y = (-5/3)x + 13/3 ------> slope -5/3 This line is parallel 6x - 10y = 7 ------> y = (6/10)x - 7/10 = (3/5)x -7/10 ------> slope 3/5 Since (-5/3)(3/5) = -1 this line is perpendicular.