Ind.Independent PracticeUse any method you choose to solve the equation.mulaUse an.3x+2x-4=0(A.A. -0.87, -1.54-0.87. -16andOB.-0.87. 1.54C. 0.87, 1.54D. 0.87,-1.54

Answer:[tex]x=-\frac{1-\sqrt{13} }{3} ,-\frac{1+\sqrt{13} }{3}[/tex][tex]0.87, -1.54[/tex]Step-by-step explanation:[tex]3x^2+2x-4=0[/tex]Use the quadratic formula:[tex]x=\frac{-b+\sqrt{b^2-4ac} }{2a} ,\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex][tex]x=\frac{-2+\sqrt{2^2-4*3*-4} }{2*3} ,\frac{-2-\sqrt{2^2-4*3*-4} }{2*3}[/tex]Simplify:[tex]x=\frac{-2+2\sqrt{13} }{6} ,\frac{-2-2\sqrt{13} }{6}[/tex][tex]x=-\frac{1-\sqrt{13} }{3} ,-\frac{1+\sqrt{13} }{3}[/tex]