On the River current a canoe traveled 30 km in 3 hours and 20 min, against the current the canoe traveled 28 km in 4 hours. how far will the canoe go in 1.5 hours on the lake?

Answer:12 kmStep-by-step explanation:Letx km/h = speed of the canoe on the lakey km/h = speed of the currentWith the current:Speed = x + y km/hDistance = 30 kmTime = 3 hours 20 minutes = [tex]3\dfrac{1}{3}[/tex] hoursThus,[tex]30=3\dfrac{1}{3}(x+y)\\ \\30=\dfrac{10}{3}(x+y)\\ \\90=10(x+y)\\ \\x+y=9[/tex]Against the current:Speed = x - y km/hDistance = 28 kmTime = 4 hours Thus,[tex]28=4(x-y)\\ \\x-y=7[/tex]Add these two equations:[tex]x+y+x-y=9+7\\ \\2x=16\\ \\x=8\ km/h[/tex]On the lake:Time = 1.5 hours Speed = 8 km/hDistance [tex]=8\cdot 1.5=12\ km[/tex]