Randy drove 540 miles in three times the time it took Andy to travel 135 miles Andy’s speed was slower than Randy’s by 15 miles per hour what were the rate and time of each?I really need help please!!!

Let's assume Randy's speed =x mphwe have Andy’s speed was slower than Randy’s by 15 miles per hourso, Andy's speed =x-15Randy drove 540 milesso, we can find time taken by Randytime = distance / speedso, we get [tex]t_R=\frac{540}{x}[/tex]we can find time taken by Andytime = distance / speedso, we get [tex]t_A=\frac{135}{x-15}[/tex]Randy drove 540 miles in three times the time it took Andy to travel 135 milesso, [tex]t_R=3t_A[/tex]we can plug it [tex]\frac{540}{x}=3*\frac{135}{x-15}[/tex]now, we can solve for x[tex]540\left(x-15\right)=405x[/tex][tex]135x=8100[/tex][tex]x=60[/tex]so, Calculation of rate:Randy's speed is 60 mphAndy's speed =x-15Andy's speed =60-15=45mphCalculation of time:Randy's time is [tex]t_R=\frac{540}{x}[/tex][tex]t_R=\frac{540}{60}[/tex][tex]t_R=9 hours[/tex]Andy's time is [tex]t_A=\frac{135}{x-15}[/tex][tex]t_A=\frac{135}{60-15}[/tex][tex]t_A=3 hours [/tex]