SOLVE for x in the equation x^2+11x+121/4+125/4

Given

[tex]x^2+11x+\frac{121}{4}=\frac{125}{4} \\ \\ \Rightarrow x^2+11x+\frac{121}{4}-\frac{125}{4}=0 \\ \\ \Rightarrow x^2+11x-1=0 \\ \\ \Rightarrow x= \frac{-11\pm\sqrt{11^2-4(1)(-1)}}{2(1)} \\ \\ = \frac{-11\pm\sqrt{121+4}}{2} = \frac{-11\pm\sqrt{125}}{2} \\ \\ = \frac{-11\pm5\sqrt{5}}{2} [/tex]