Suppose that 9 green balls and 13 purple balls are placed in an urn. two balls are then drawn in succession. what is the probability that both balls drawn have the same color if the first ball is replaced before the second is drawn?

Question
Answer:
Total balls = 9 + 13 = 22

P(both green or both purple) = (9/22)(9/22) + (13/22)(13/22) = 125/242

Answer: 125/242
solved
general 11 months ago 6690