The rectangle shown has a perimeter of 34 cm and the area given its length is 5 more than twice the width write and solve a system of equations to find the dimensions of the rectangle a=52cm^2
Question
Answer:
2(2w+5) + 2W =344w+10+2w=34
6W+10=34
-10 -10
6w=24
Width =4
Length =13
solved
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10 months ago
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