Two cars leave towns 760 kilometers apart at the same time and travel toward each other. one car's rate is 18 kilometers per hour less than the other's. if they meet in 4 hours, what is the rate of the slower car?

Let s be the speed of the first car; and s-18 be the speed of the other. Then:
760/(s+s-18)=4
760=8s-72
8s=832
s=104
The first car goes 104 kph; the second car goes 86 kph
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