Using the technique in the model above, find the missing segments in this 30°-60°-90° right triangle.AD = 6 DB = 2 AC =

For this case what you should do is use the following trigonometric relationship:
 [tex] cos (x) = \frac{C.A}{h} [/tex]
 Where
 x: angle
 C.O: adjoining cathetus
 h: hypotenuse
 Substituting the values we have:
 [tex] cos (x) = \frac{AD}{AC} [/tex]
 [tex] cos (30) = \frac{6}{AC} [/tex]
 [tex] AC = \frac{6}{cos30} [/tex]
 [tex] AC = 6.93 [/tex]
 Answer: 
 [tex] AC = 6.93[/tex]