what are the focus and directrix of the parabola with the given equation x=-1/8y^2

If the equation of the parabola is y² = -8x. Then the focus is at (-2, 0) and the directrix is at x = 2.What is the parabola?It is the locus of a point that moves so that it is always the same distance from a non-movable point and a given line. The non-movable point is called focus and the non-movable line is called the directrix.The equation of the parabola is given below.[tex]\rm x=-\dfrac{1}{8} \times y^2[/tex]On simplifying, we have [tex]\rm y^2 = -8x\\\\y^2 = -4(2)x[/tex] ...1We know that equation of the parabola [tex]\rm y^2 = -4ax[/tex] ...2Then the directrix is at x = a and the focus will be (-a, 0)Compare equations 1 and 2, we have a = 2Then the focus is at (-2, 0) and the directrix is at x = 2.More about the parabola link is given below.