what is the equation in standard form of the line that passes through the point (4,-8) and has a slope of 1/4
Question
Answer:
y = mx + bslope(m) = 1/4
(4,-8)....x = 4 and y = -8
now sub and find b, the y int
-8 = 1/4(4) + b
-8 = 1 + b
-8 - 1 = b
-9 = b
so ur equation is : y = 1/4x - 9....but we need it in standard form
y = 1/4x - 9
-1/4x + y = -9...multiply everything by -4
x - 4y = 36 <====
solved
general
11 months ago
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