What is the equation of the line, in point-slope form, that passes through the given point and has the given slope? Point (11, 3) slope: 9y - 3 = 9(x + 11)y - 3 = 9(x - 11)y - 3 = -9(x - 11)y - 11 = 9(x - 3)Solve the equation or formula for the indicated variables=6r^3t, for t

Answer:OPTION BStep-by-step explanation:When a point on a line and the slope of the line are given the equation of the line is determined using the slope one- point form                           [tex]$ (y - y_1) = m(x - x_1) $[/tex]where, m = slope of the lineand [tex]$ (x_1,y_1) $[/tex] is the point passing through it.Here [tex]$ (x_1,y_1) = (11,3) $[/tex] and [tex]$ m = 9 $[/tex].Substituting in the formula we have: [tex]$ (y - 3) = 9(x - 11) $[/tex]This is OPTION B. Hence, the answer.