What is the length of segment BC? A coordinate plane is shown. Point B is located at negative 3, negative 2, and point C is located at 0, 2. The points are connected by a line segment. 4 units 5 units 6 units 7 units

we have that

point B (-3,-2)
point C (0,2)
the distance between B and C is
d=√(y2-y1)²+(x2-x1)²--------> d= √(2+2)²+(0+3)²-------> d=√25
d=5 units

the answer is 
the length of segment BC is 5 units

using a graph tool
see the attached figure