what is the sum of the measures of the interior angles of a convex 68-gon

Sum of interior angles = (n - 2) * 180 degrees In this formula, "n" represents the number of sides (in this case, 68 for a 68-gon). So, for a convex 68-gon: Sum of interior angles = (68 - 2) * 180 degrees Sum of interior angles = 66 * 180 degrees Sum of interior angles = 11,880 degrees The sum of the measures of the interior angles of a convex 68-gon is 11,880 degrees