What is the value of h when the function is converted to vertex form? Note: Vertex form is p(x)=a(x−h)2+k . p(x)=x2−14x+29 Enter your answer in the box.

Answer:p(x) = (x - 7)^2 -20 Step-by-step explanation:Convert p(x)=x^2−14x+29 to vertex form, to resemble y = (x - h)^2 + k, where (h, k) is the vertex:1. Rewrite p(x)=x^2−14x+29 as p(x)=x^2 − 14x +                                   +292. Identify the coefficient of the x term:  It is -14.3.  Take HALF of this coefficient:  it is -74.  Square this result, obtaining 495.  Add this to x^2 − 14x and then subtract it, keeping the +29:     x^2 - 14x + 49 - 49 + 296.  Rewrite the first three terms as the square of a binomial:      p(x) = (x - 7)^2           -49 + 29, or       p(x) = (x - 7)^2 -20      This is the desired result (answer).7.   If you want to  identify the vertex, compare this    p(x) = (x - 7)^2 -20 to the standard form       f(x) = (x - h)^2 + k               Then h = 7 and k = -20.8.    The vertex of the parabolic graph of this function is (7, -20).