Which are the solutions of the quadratic equation? x2 = 7x + 4 –7, 0 7, 0

Answer:[tex]x=\frac{7+\sqrt{65}}{2}, x=\frac{7-\sqrt{65}}{2}[/tex]Step-by-step explanation:We are given that a quadratic equation [tex]x^2=7x+4[/tex][tex]x^2-7x-4=0[/tex]We have to find the solutions of the quadratic equation.a=1, b=-7,v=-4Quadratic formula:[tex]x=\frac{-b\pm\sqrt{b^2-4ac}{2a}[/tex]Substitute the values in the quadratic formula [tex]x=\frac{-(-7)\pm\sqrt{(-7)^2-4(1)(-4)}}{2(1)}[/tex][tex]x=\frac{7\pm\sqrt{49+16}}{2}[/tex][tex]x=\frac{7\pm\sqrt{65}}{2}[/tex][tex]x=\frac{7+\sqrt{65}}{2}, x=\frac{7-\sqrt{65}}{2}[/tex]Hence, the solutions of quadratic equation are[tex]x=\frac{7+\sqrt{65}}{2}, x=\frac{7-\sqrt{65}}{2}[/tex]