Which equation is equivalent to log4 + log(x + 2) = 1?x - 2 = 1014x + 8 = 1014x + 8 = 14/x+2=10^1

We have the following expression:
 log4 + log (x + 2) = 1
 By properties of logarithm we can rewrite the expression as:
 log (4 * (x + 2)) = 1
 Then, Rewriting we have:
 10 ^ (log (4 * (x + 2))) = 10 ^ 1
 4 * (x + 2) = 10 ^ 1
 Rewriting:
 4x + 8 = 10 ^ 1
 Answer:
 The equivalent expression is:
 4x + 8 = 10 ^ 1