Which of the following values of x satisfy the equation 3x^2-8x+4=0

[tex]3x^2-8x+4=0\\\\\Delta=b^2-4ac=(-8)^2-4\times3\times4=64-48=16\\\\x_1=\dfrac{-b+\sqrt{\Delta}}{2a}=\dfrac{8-4}{6}=\dfrac{4}{6}=\dfrac{2}{3}\\\\x_2=\dfrac{-b-\sqrt{\Delta}}{2a}=\dfrac{8+4}{6}=\dfrac{12}{6}=2\\\\\boxed{S=\left\{\dfrac{2}{3};2\right\}}[/tex]