From rest, a jeepney accelerates uniformly over a time of 3.25 seconds and covers a distance of 15 m. Determine the acceleration of the jeepney. Given: vi=0 m/s d=15 m t=3.25 s Find: a= ? Solution: d=vit+1/2 at2 15 m=0 m/s3.25 s+1/2 a3.25 s2 15 m=5.28s2a a=15 m/5.28 s2 a=underline
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