What is the following product? RootIndex 3 StartRoot 16 x Superscript 7 Baseline EndRoot times RootIndex 3 StartRoot 12 x Superscript 9 Baseline EndRoot

Answer:[tex] 4x^5\sqrt[3]{3x} [/tex]Step-by-step explanation:I'm not sure I understand the problem, but I think it's this:[tex] \sqrt[3]{16x^7} \times \sqrt[3]{12x^9} = [/tex][tex]= \sqrt[3]{16 \times 12 \times x^{16}}[/tex][tex]= \sqrt[3]{192 \times x^{15} \times x}[/tex][tex] = \sqrt[3]{64 \times 3 \times (x^5)^3 \times x} [/tex][tex] = \sqrt[3]{4^3 \times 3 \times (x^5)^3 \times x} [/tex][tex] = 4x^5\sqrt[3]{3x} [/tex]