The table of values represents a polynomial function f(x).How much greater is the average rate of change over the interval [7, 9] than the interval [4, 6] ?
Question
Answer:
average rate = (f(final)-f(initial))/(x(final)-x(initial))the interval [7, 9]
av. rate =(3878-1852)/(9-7)=1013
the interval [4, 6]
av. rate =(1178-358)/(6-4)=410
1013-410=603 greater the average rate of change over the interval [7, 9] than the interval [4, 6]
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11 months ago
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