A car enters a freeway with a speed of 6.5 m/s and accelerates to a speed of 24 m/s in 3.5 min how far does the car travel while it is accelerating

the acceleration is given by:
a=(v2-v1)/t
where
a=accelaration
v2=second velocity
v1=first velocity
thus the acceleration will be:
v1=6.5 m/s
v2=24 m/s
t=3.5min=210 sec

thus
a=(24-6.5)/210
a=0.09286 m/s²

Answer: 0.09286 m/s²