The heights of adult women are approximately normally distributed about a mean of 65 inches with a standard deviation of 2 inches. if rachael is at the 99th percentile in height for adult women, then her height, in inches, is closest to:

Answer:69.65 inches Step-by-step explanation:Mean = [tex]\mu = 65[/tex]Standard deviation = [tex]\sigma = 2[/tex]Now we are supposed to find if Rachael is at the 99th percentile in height for adult women, then her height, in inchesFormula : [tex]z =\frac{x-\mu}{\sigma}[/tex] z at 99th percentile =2.326Substitute the values in the formula [tex]2.326=\frac{x-65}{2}[/tex] [tex]2.326 \times 2=x-65[/tex] [tex]4.652=x-65[/tex] [tex]4.652+65=x[/tex] [tex]69.65=x[/tex] Hence her height is 69.65 inches .