A greeting card uses a geometric design containing 4 congruent kites. The card is 4 inches wide and 8 inches long. What is the area of one kite? 4 sq. in. 8 sq. in. 12 sq. in. 16 sq. in.

Answer: 4 sq. inStep-by-step explanation:From the question, the card is 8 inches long. Therefore, the length of the vertical diagonal of 1 kite + the length of the vertical diagonal of other kite = 8Since we have been told that the kites are congruent, therefore the length of the vertical diagonal of both kites will be thesameTherefore, 2(length of the vertical diagonal of 1 kite) = 8Therefore, the length of the vertical diagonal of 1 kite will be= 4 inchesThe width of the card = 4 inchesTherefore, the length of the horizontal diagonal of 1 kite + the length of the horizontal diagonal of another kite =4Since the kites are congruent, therefore, the length of the horizontal diagonal of both kites are the sameTherefore, 2(length of the horizontal diagonal of 1 kite) = 4Therefore, the length of the horizontal diagonal of 1 kite will be= 2 inchesTherefore, the length of the vertical diagonal of the kite= 4 inches and the horizontal diagonal= 2 inchesSo, Area of kite = pq/2Where p and q are diagonals of kiteArea of kite = (4×2)/2=8/2= 4 inches square