An astronaut drops a rock into a crater on the moon. The distance, d(t), in meters, the rock travels after t seconds can be modeled by the function d(t)=0.8t^2 . What is the average speed, in meters per second, of the rock between 5 and 10 seconds after it was dropped?

Plug in 5 and 10 to the equation.For the first one would be d(5)=0.8(5)^2. Multiply the equation, d(5)=4^2. Then you just multiply the exponent and the answer would be, d(5)= 10The second one, you just do the same thing and the answer would be d(10)= 64