Can someone please help me with this, marking brainliest and giving 15 points!The distance traveled of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 3 to t = 6 represent? (2 points)The coin falls down with an average speed of 132.3 meters per second from 3 seconds to 6 seconds.The coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.The coin travels an average distance of 132.3 meters from 3 seconds to 6 seconds.The coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds.

Question
Answer:
change in distance = 176.4 - 44.1 = 132.3
change in time = 6 - 3 = 3

The object travels 132.3 meters in 3 seconds

the speed is the ratio of the two values

speed = distance/time
speed = 132.3/3
speed = 44.1 meters per second

This is the average speed of the object from t = 3 to t = 6 seconds. This is equivalent to the slope of the straight line through the two points.

The answer is The coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.`
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