Factor to find the zeros of the function defined by the quadratic expression. 9x2 β 63x β 702
Question
Answer:
Not that it will help all that much, but you could take out 9 as a common factor.9(x^2 - 7x - 78) = 0 so since 9 but itself can't produce a zero, we can divide by 9
x^2 - 7x - 78 = 0Β
There are 3 factors of 78
2 13 and 3
6 and 13 differ by 7 (6 comes from putting the 2 and 3 together by multiplying.
(x - 13)(x + 6) = 0Β
x -13 =0
x = 13
x + 6 = 0
x = - 6
The two zeros are (-6,0) and (13,0)
solved
general
10 months ago
6054