Find f^-1(x) for f(x)=1/x^3 and state whether or not it is a function.

To find the inverse of a function, switch the x and y (the f(x) =y) then solve for y.

x = 1/(y^3)

xy^3 = 1

y^3 = 1/x

f^-1(x) = y = 1/x^(1/3)

Note: 1/3 power is the same as cube root.

Yes it is a function