Find the coordinates of the points of intersection of the graphs without building them: 5xβ4y=16 and xβ2y=6
Question
Answer:
we have thatequation 1
5xβ4y=16
and
equation 2
xβ2y=6
we know that
Part A) the x-intercept is when y=0
equation 1
5xβ4y=16
for y=0
5x=16--------> x=16/5---> x=3.2
the point is (3.2,0)
equation 2
xβ2y=6
for y=0
x=6
the point is (6,0)
Part B) the y-intercept is when x=0
equation 1
5xβ4y=16
for x=0
-4y=16-------> y=-4
the point is (0,-4)
equation 2
xβ2y=6
for x=0
-2y=6------> y=-3
the point is (0,-3)
the answer is
the coordinates of the points of intersection are
equation 1
5xβ4y=16
(3.2,0)Β and (0,-4)
equation 2
xβ2y=6
(6,0) and (0,-3)
solved
general
11 months ago
4662