I need help with these 4 questions on my math homework! I have some examples with it but I still don't know how to do them... (Solved)

Step-by-step explanation: For equation N°2 [tex]-x-3 = 0\\[/tex] Solving algebraically: [tex]-x + x -3 = x[/tex] (Sum x on both sides of the equation) [tex]-3 = x\\[/tex]
Resolving graphically: x = -2 --------- - (- 2) -3 = -1 pto (-2, -1) x = -4 ---------- - (- 4) -3 = 1 pt (-4.1) x = -3 --------- - (- 3) -3 = 0 pt (-3.0) Solution The graphic is shown in the attached image. The red dot in the graph represents the solution
For equation N° 4 [tex]9x +3 = 0\\[/tex] Solving algebraically: [tex]9x+3 -3 = -3[/tex] (Sum -3 on both sides of the equation) [tex]9x =-3[/tex]
[tex]\frac{9x}{9}=\frac{-3}{9}[/tex] (divided by 9 on both sides of the equation) [tex]x =\frac{-3}{9}[/tex] (simplifies the fraction) [tex]x =\frac{-1}{3}[/tex]
Resolving graphically: x = 1 --------- 9 (1) +3 = 12 pt (1.12) x = -1 --------- 9 (-1) +3 = -6 pto (-1, -6) x = -1 / 3 -------- 9 (-1/3) +3 = 1 pt (-1 / 3.0) Solution The graphic is shown in the attached image. The red dot in the graph represents the solution
For equation N°. 6. [tex]4x + 11 = 4x-24\\[/tex] Solving algebraically: [tex]4x -4x +11 = 4x -4x-24[/tex] (Sum -4x on both sides of the equation) [tex]11 = -24[/tex] The equation is not met, the x are eliminated, therefore, it has solution
For equation N°. 8 [tex]-6x +3 = -6x + 5\\[/tex] Solving algebraically: [tex]-6x + 6x +3 = -6x + 6x +5[/tex] (Sum 6x on both sides of the equation) [tex]3 = 5[/tex] The x are eliminated, 3 is not equal to 5, the equality is not met. The equation has no solution.