Find the value of z such that 0.9426 of the area lies between −z−z and z. Round your answer to two decimal places.

The z-score is the number of standard deviations away from the mean that a data point is. To find the value of z for which 0.9426 of values are within z deviations of the mean, this means that (1 - 0.9426) = 0.0584 are beyond this interval, and this would be divided by 2: 0.0584 / 2 = 0.0292 of values are located below -z, while another 0.0292 is above +z.
Based on z-tables, this occurs at around z = 1.89, so the interval is from -1.89 to 1.89.