harry invests £6000 in a savings account. the account pays 3.4% compound interest per year. work out the value of his investment per year. work out the value of his investment after 3 years. give your answer to the nearst penny.

Invested amount (P0 = £6000.Rate of interest (r) = 3.4% = 0.034.We know compound interest formula A = P(1+r)^tWe need work out the value of his investment per year. So, we need to plug t=1 and plugging values of P and r in the formula above, we get A = 6000(1+0.034)^1A = 6000(1.034) A = 6204.Therefore, the value of his investment per year is £ 6204.Now, we need to work out the value of his investment after 3 years.So, we need to plug t=3.A = 6000(1+0.034)^3A = 6000(1.034)^31.034^3=1.105507304A = 6000 × 1.105507304A = 6633.04 Therefore, the value of his investment after 3 year is  £ 6633.04.