HELP PLEASEMATH QUESTION

Answer:[tex]\displaystyle 11,7\:cm. ≈ AC[/tex]○ [tex]\displaystyle ∠E[/tex]Step-by-step explanation:When you draw your triangle, based on the information given to you, you will end up having to use the secant [or cosine] trigonometric ratio. Here is how it is done:[tex]\displaystyle \frac{14}{AC} = sec\:33 \hookrightarrow 14 = ACsec\:33 \hookrightarrow \frac{14}{sec\:33} = AC; 11,741387951... = AC \\ \\ 11,7 ≈ AC[/tex]OR[tex]\displaystyle \frac{AC}{14} = cos\:33 \hookrightarrow 14cos\:33 = AC; 11,741387951... = AC \\ \\ 11,7 ≈ AC[/tex] Extended information on trigonometric ratios [tex]\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ[/tex]Well, there you have it! With all of this information, you should be capable of understanding the concept.I am joyous to assist you at any time.